What are the solutions to the equation -λ^3+10λ^2-33λ+36=0 ?

The solutions to the equation -λ^3+10λ^2-33λ+36=0 are λ=3,λ=4

Find the zeros of -λ^3+10λ^2-33λ+36=0

The zeros of -λ^3+10λ^2-33λ+36=0 are λ=3,λ=4

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- λ^{3} + 10 λ^{2} - 33 λ + 36 = 0

λ = 3, λ = 4

Solution steps

- λ^{3} + 10 λ^{2} - 33 λ + 36 = 0

Factor

- λ^{3} + 10 λ^{2} - 33 λ + 36 : - (λ - 3)^{2} (λ - 4)

- (λ - 3)^{2} (λ - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ - 3 = 0 or λ - 4 = 0

Solve

λ - 3 = 0 : λ = 3

Solve

λ - 4 = 0 : λ = 4

The solutions are

λ = 3, λ = 4

0 = - 4 x^{3} + 2 x^{2} + x - 2

2 s^{4} + 48 s^{2} - 50 = 0

x^{3} + 4 x^{2} - 10 x - 40 = 0

2 x^{3} + 10 x^{2} + 4 x = - 8 x

x, x^{3} - 3 x^{2} + x = 0

What are the solutions to the equation -λ^3+10λ^2-33λ+36=0 ?
The solutions to the equation -λ^3+10λ^2-33λ+36=0 are λ=3,λ=4
Find the zeros of -λ^3+10λ^2-33λ+36=0
The zeros of -λ^3+10λ^2-33λ+36=0 are λ=3,λ=4