What are the solutions to the equation 0=x(x+5)(x^2-8x-19) ?

The solutions to the equation 0=x(x+5)(x^2-8x-19) are x=0,x=-5,x=4+sqrt(35),x=4-sqrt(35)

Find the zeros of 0=x(x+5)(x^2-8x-19)

The zeros of 0=x(x+5)(x^2-8x-19) are x=0,x=-5,x=4+sqrt(35),x=4-sqrt(35)

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0 = x (x + 5) (x^{2} - 8 x - 19)

x = 0, x = - 5, x = 4 + 35, x = 4 - 35

Decimal Notation

x = 0, x = - 5, x = 9.91607 \dots, x = - 1.91607 \dots

Solution steps

0 = x (x + 5) (x^{2} - 8 x - 19)

Switch sides

x (x + 5) (x^{2} - 8 x - 19) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 5 = 0 or x^{2} - 8 x - 19 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x^{2} - 8 x - 19 = 0 : x = 4 + 35, x = 4 - 35

The solutions are

x = 0, x = - 5, x = 4 + 35, x = 4 - 35

x^{4} + 2 x^{3} - 9 x^{2} - 10 x - 24 = 0

m, m^{3} - 3 m - 26 = 0

2 x^{4} - 3 x^{3} - 15 x^{2} + 32 x - 12 = 0

x^{3} - x + 13 = 0

n^{3} = (1000000)

What are the solutions to the equation 0=x(x+5)(x^2-8x-19) ?
The solutions to the equation 0=x(x+5)(x^2-8x-19) are x=0,x=-5,x=4+sqrt(35),x=4-sqrt(35)
Find the zeros of 0=x(x+5)(x^2-8x-19)
The zeros of 0=x(x+5)(x^2-8x-19) are x=0,x=-5,x=4+sqrt(35),x=4-sqrt(35)