What are the solutions to the equation -3x^4+18x^3+48x^2=0 ?

The solutions to the equation -3x^4+18x^3+48x^2=0 are x=0,x=-2,x=8

Find the zeros of -3x^4+18x^3+48x^2=0

The zeros of -3x^4+18x^3+48x^2=0 are x=0,x=-2,x=8

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- 3 x^{4} + 18 x^{3} + 48 x^{2} = 0

x = 0, x = - 2, x = 8

Solution steps

- 3 x^{4} + 18 x^{3} + 48 x^{2} = 0

Factor

- 3 x^{4} + 18 x^{3} + 48 x^{2} : - 3 x^{2} (x + 2) (x - 8)

- 3 x^{2} (x + 2) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 8 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 8 = 0 : x = 8

The solutions are

x = 0, x = - 2, x = 8

x^{3} + 7 x - 5 = 0

x^{3} - 3 x + 16 = 0

y^{3} + 2 y = 9 y + 18

8 X^{3} + 10 X^{2} - 10 = 0

x^{3} + 5 x + \frac{55}{18} = 0

What are the solutions to the equation -3x^4+18x^3+48x^2=0 ?
The solutions to the equation -3x^4+18x^3+48x^2=0 are x=0,x=-2,x=8
Find the zeros of -3x^4+18x^3+48x^2=0
The zeros of -3x^4+18x^3+48x^2=0 are x=0,x=-2,x=8