What are the solutions to the equation 49t^4+44t^2-5=0 ?

The solutions to the equation 49t^4+44t^2-5=0 are t=(sqrt(5))/7 ,t=-(sqrt(5))/7 ,t=i,t=-i

Find the zeros of 49t^4+44t^2-5=0

The zeros of 49t^4+44t^2-5=0 are t=(sqrt(5))/7 ,t=-(sqrt(5))/7 ,t=i,t=-i

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49 t^{4} + 44 t^{2} - 5 = 0

t = \frac{5}{7}, t = - \frac{5}{7}, t = i, t = - i

Solution steps

49 t^{4} + 44 t^{2} - 5 = 0

Rewrite the equation with

u = t^{2}

and

u^{2} = t^{4}

49 u^{2} + 44 u - 5 = 0

Solve

49 u^{2} + 44 u - 5 = 0 : u = \frac{5}{49}, u = - 1

u = \frac{5}{49}, u = - 1

Substitute back

u = t^{2},

solve for

t

Solve

t^{2} = \frac{5}{49} : t = \frac{5}{7}, t = - \frac{5}{7}

Solve

t^{2} = - 1 : t = i, t = - i

The solutions are

t = \frac{5}{7}, t = - \frac{5}{7}, t = i, t = - i

12 x (x^{2} - 1)^{2} = 0

x^{4} = - 16 i

\frac{64}{81} = 4 q^{4}

(- 3) (x) = 3 x^{3} + 5

6 x^{5} - 4 x^{3} + 1 = 0

What are the solutions to the equation 49t^4+44t^2-5=0 ?
The solutions to the equation 49t^4+44t^2-5=0 are t=(sqrt(5))/7 ,t=-(sqrt(5))/7 ,t=i,t=-i
Find the zeros of 49t^4+44t^2-5=0
The zeros of 49t^4+44t^2-5=0 are t=(sqrt(5))/7 ,t=-(sqrt(5))/7 ,t=i,t=-i