What are the solutions to the equation c^3-5c^2+7c-9=100 ?

The solutions to the equation c^3-5c^2+7c-9=100 are c\approx 6.50181…

Find the zeros of c^3-5c^2+7c-9=100

The zeros of c^3-5c^2+7c-9=100 are c\approx 6.50181…

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c^{3} - 5 c^{2} + 7 c - 9 = 100

c \approx 6.50181 \dots

Solution steps

c^{3} - 5 c^{2} + 7 c - 9 = 100

Move

100

to the left side

c^{3} - 5 c^{2} + 7 c - 109 = 0

Find one solution for

c^{3} - 5 c^{2} + 7 c - 109 = 0

using Newton-Raphson:

c \approx 6.50181 \dots

Apply long division:

\frac{c ^{3} - 5 c ^{2} + 7 c - 109}{c - 6.50181 \dots} = c^{2} + 1.50181 \dots c + 16.76454 \dots

c^{2} + 1.50181 \dots c + 16.76454 \dots \approx 0

Find one solution for

c^{2} + 1.50181 \dots c + 16.76454 \dots = 0

using Newton-Raphson:

No Solution for

c \in R

The solution is

c \approx 6.50181 \dots

25 x^{3} - 50 x^{2} - 4 x + 8 = 0

3 - (x - 1)^{4} = 0

p^{3} - 49 p = 0

8 = x^{4} - 2 x^{2}

9.1 = x^{3} - 2 x + 5

What are the solutions to the equation c^3-5c^2+7c-9=100 ?
The solutions to the equation c^3-5c^2+7c-9=100 are c\approx 6.50181…
Find the zeros of c^3-5c^2+7c-9=100
The zeros of c^3-5c^2+7c-9=100 are c\approx 6.50181…