What are the solutions to the equation 5y^3-29y^2-6y=0 ?

The solutions to the equation 5y^3-29y^2-6y=0 are y=0,y=-1/5 ,y=6

Find the zeros of 5y^3-29y^2-6y=0

The zeros of 5y^3-29y^2-6y=0 are y=0,y=-1/5 ,y=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 y^{3} - 29 y^{2} - 6 y = 0

y = 0, y = - \frac{1}{5}, y = 6

Decimal Notation

y = 0, y = - 0.2, y = 6

Solution steps

5 y^{3} - 29 y^{2} - 6 y = 0

Factor

5 y^{3} - 29 y^{2} - 6 y : y (5 y + 1) (y - 6)

y (5 y + 1) (y - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 5 y + 1 = 0 or y - 6 = 0

Solve

5 y + 1 = 0 : y = - \frac{1}{5}

Solve

y - 6 = 0 : y = 6

The solutions are

y = 0, y = - \frac{1}{5}, y = 6

2 x^{3} - 23 = 35

x^{3} = 4 x^{2} + 5 x

x^{4} - 7 x^{2} - 12 = 0

n^{3} = 512729

9 x^{4} - 75 x^{3} + 126 x^{2} = 0

What are the solutions to the equation 5y^3-29y^2-6y=0 ?
The solutions to the equation 5y^3-29y^2-6y=0 are y=0,y=-1/5 ,y=6
Find the zeros of 5y^3-29y^2-6y=0
The zeros of 5y^3-29y^2-6y=0 are y=0,y=-1/5 ,y=6