What are the solutions to the equation b^3-125=0 ?

The solutions to the equation b^3-125=0 are b=5,b=-5/2+(5sqrt(3))/2 i,b=-5/2-(5sqrt(3))/2 i

Find the zeros of b^3-125=0

The zeros of b^3-125=0 are b=5,b=-5/2+(5sqrt(3))/2 i,b=-5/2-(5sqrt(3))/2 i

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b^{3} - 125 = 0

b = 5, b = - \frac{5}{2} + \frac{5 3}{2} i, b = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

b^{3} - 125 = 0

Move

125

to the right side

b^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

b = 5, b = - \frac{5}{2} + \frac{5 3}{2} i, b = - \frac{5}{2} - \frac{5 3}{2} i

4 x^{3} - 8 x^{2} + 5 x - 73 = 0

x (x - 2) (x + 5) = 0

- 9 = \frac{5}{4} x^{45} x

2 x^{3} - 3 x^{2} + 3 x + 2 = 0

10 + 10 x - 2 x^{2} - 2 x^{3} = 0

What are the solutions to the equation b^3-125=0 ?
The solutions to the equation b^3-125=0 are b=5,b=-5/2+(5sqrt(3))/2 i,b=-5/2-(5sqrt(3))/2 i
Find the zeros of b^3-125=0
The zeros of b^3-125=0 are b=5,b=-5/2+(5sqrt(3))/2 i,b=-5/2-(5sqrt(3))/2 i