What are the solutions to the equation x^3-4x^2-2x+20=0 ?

The solutions to the equation x^3-4x^2-2x+20=0 are x=-2,x=3+i,x=3-i

Find the zeros of x^3-4x^2-2x+20=0

The zeros of x^3-4x^2-2x+20=0 are x=-2,x=3+i,x=3-i

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x^{3} - 4 x^{2} - 2 x + 20 = 0

x = - 2, x = 3 + i, x = 3 - i

Solution steps

x^{3} - 4 x^{2} - 2 x + 20 = 0

Factor

x^{3} - 4 x^{2} - 2 x + 20 : (x + 2) (x^{2} - 6 x + 10)

(x + 2) (x^{2} - 6 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} - 6 x + 10 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} - 6 x + 10 = 0 : x = 3 + i, x = 3 - i

The solutions are

x = - 2, x = 3 + i, x = 3 - i

x, 2 x^{3} - 3 y - 16 = 0

x, x^{6} = \frac{9}{4}

x, x^{2} (m - 2) x + 2 m - 8 = 0

(x - 2)^{2} (x - 3) (x + 1) = 0

4 x^{5} - 25 x^{3} = 0

What are the solutions to the equation x^3-4x^2-2x+20=0 ?
The solutions to the equation x^3-4x^2-2x+20=0 are x=-2,x=3+i,x=3-i
Find the zeros of x^3-4x^2-2x+20=0
The zeros of x^3-4x^2-2x+20=0 are x=-2,x=3+i,x=3-i