What are the solutions to the equation 2x^3+3x-5=0 ?

The solutions to the equation 2x^3+3x-5=0 are x=1,x=-1/2+i 3/2 ,x=-1/2-i 3/2

Find the zeros of 2x^3+3x-5=0

The zeros of 2x^3+3x-5=0 are x=1,x=-1/2+i 3/2 ,x=-1/2-i 3/2

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2 x^{3} + 3 x - 5 = 0

x = 1, x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

2 x^{3} + 3 x - 5 = 0

Factor

2 x^{3} + 3 x - 5 : (x - 1) (2 x^{2} + 2 x + 5)

(x - 1) (2 x^{2} + 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x^{2} + 2 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x^{2} + 2 x + 5 = 0 : x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

The solutions are

x = 1, x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

(1 - r)^{3} = 3 - 3 r

x^{3} - 5 x^{2} + 4 x + 10 = 0

x^{6} - 22 x^{3} + 49 = 0

5 x^{3} - 125 x^{5} = 0

(x^{2} + x)^{2} = 5 x^{2} + 5 x - 6

What are the solutions to the equation 2x^3+3x-5=0 ?
The solutions to the equation 2x^3+3x-5=0 are x=1,x=-1/2+i 3/2 ,x=-1/2-i 3/2
Find the zeros of 2x^3+3x-5=0
The zeros of 2x^3+3x-5=0 are x=1,x=-1/2+i 3/2 ,x=-1/2-i 3/2