What are the solutions to the equation x^2(x-1)+2x=0 ?

The solutions to the equation x^2(x-1)+2x=0 are x=0,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

Find the zeros of x^2(x-1)+2x=0

The zeros of x^2(x-1)+2x=0 are x=0,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} (x - 1) + 2 x = 0

x = 0, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{2} (x - 1) + 2 x = 0

Factor

x^{2} (x - 1) + 2 x : x (x^{2} - x + 2)

x (x^{2} - x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - x + 2 = 0

Solve

x^{2} - x + 2 = 0 : x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

The solutions are

x = 0, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

20 x^{3} + 12 x^{2} - 12 x - 2 = 0

4 x^{3} - 12 x + 8 = 0

z^{4} = 16 (1 + j^{2})

27 = v^{3}

x^{4} - 13 x^{3} + 36 = 0

What are the solutions to the equation x^2(x-1)+2x=0 ?
The solutions to the equation x^2(x-1)+2x=0 are x=0,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2
Find the zeros of x^2(x-1)+2x=0
The zeros of x^2(x-1)+2x=0 are x=0,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2