What are the solutions to the equation 2y^4+3y^3-16y^2+15y-4=0 ?

The solutions to the equation 2y^4+3y^3-16y^2+15y-4=0 are y=1,y= 1/2 ,y=-4

Find the zeros of 2y^4+3y^3-16y^2+15y-4=0

The zeros of 2y^4+3y^3-16y^2+15y-4=0 are y=1,y= 1/2 ,y=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 y^{4} + 3 y^{3} - 16 y^{2} + 15 y - 4 = 0

y = 1, y = \frac{1}{2}, y = - 4

Decimal Notation

y = 1, y = 0.5, y = - 4

Solution steps

2 y^{4} + 3 y^{3} - 16 y^{2} + 15 y - 4 = 0

Factor

2 y^{4} + 3 y^{3} - 16 y^{2} + 15 y - 4 : (y - 1)^{2} (2 y - 1) (y + 4)

(y - 1)^{2} (2 y - 1) (y + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 1 = 0 or 2 y - 1 = 0 or y + 4 = 0

Solve

y - 1 = 0 : y = 1

Solve

2 y - 1 = 0 : y = \frac{1}{2}

Solve

y + 4 = 0 : y = - 4

The solutions are

y = 1, y = \frac{1}{2}, y = - 4

(u + 4)^{3} = - (u + 4)^{2}

R, V = \frac{4}{3} π R^{3}

x^{3} = \frac{8}{343}

8 x^{10} - x^{4} - 2 = 0

m^{3} - 2 m^{2} = 0

What are the solutions to the equation 2y^4+3y^3-16y^2+15y-4=0 ?
The solutions to the equation 2y^4+3y^3-16y^2+15y-4=0 are y=1,y= 1/2 ,y=-4
Find the zeros of 2y^4+3y^3-16y^2+15y-4=0
The zeros of 2y^4+3y^3-16y^2+15y-4=0 are y=1,y= 1/2 ,y=-4