What are the solutions to the equation (r)^3=216 ?

The solutions to the equation (r)^3=216 are r=6,r=-3+3sqrt(3)i,r=-3-3sqrt(3)i

Find the zeros of (r)^3=216

The zeros of (r)^3=216 are r=6,r=-3+3sqrt(3)i,r=-3-3sqrt(3)i

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(r)^{3} = 216

r = 6, r = - 3 + 33 i, r = - 3 - 33 i

Solution steps

r^{3} = 216

For

x^{3} = f (a)

the solutions are

Simplify

r = 6, r = - 3 + 33 i, r = - 3 - 33 i

x^{3} + x^{2} + x = - 1

64 x^{3} + 216 (x - 1)^{3} = 0

x^{3} + 2 x^{2} + 6 x + 5 = 0

z^{6} - 2 z^{3} + 4 = 0

2 x (x - 2)^{2} = 0

What are the solutions to the equation (r)^3=216 ?
The solutions to the equation (r)^3=216 are r=6,r=-3+3sqrt(3)i,r=-3-3sqrt(3)i
Find the zeros of (r)^3=216
The zeros of (r)^3=216 are r=6,r=-3+3sqrt(3)i,r=-3-3sqrt(3)i