What are the solutions to the equation solvefor x,x(x+1)(x+2)=-1 ?

The solutions to the equation solvefor x,x(x+1)(x+2)=-1 are x\approx-2.32471…

Find the zeros of solvefor x,x(x+1)(x+2)=-1

The zeros of solvefor x,x(x+1)(x+2)=-1 are x\approx-2.32471…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x (x + 1) (x + 2) = - 1

x \approx - 2.32471 \dots

Solution steps

x (x + 1) (x + 2) = - 1

Expand

x (x + 1) (x + 2) : x^{3} + 3 x^{2} + 2 x

x^{3} + 3 x^{2} + 2 x = - 1

Move

1

to the left side

x^{3} + 3 x^{2} + 2 x + 1 = 0

Find one solution for

x^{3} + 3 x^{2} + 2 x + 1 = 0

using Newton-Raphson:

x \approx - 2.32471 \dots

Apply long division:

\frac{x ^{3} + 3 x ^{2} + 2 x + 1}{x + 2.32471 \dots} = x^{2} + 0.67528 \dots x + 0.43015 \dots

x^{2} + 0.67528 \dots x + 0.43015 \dots \approx 0

Find one solution for

x^{2} + 0.67528 \dots x + 0.43015 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx - 2.32471 \dots

x (x - 1) (x + 5) = 0

b^{3} - 25 b = 0

2 x^{3} - x^{2} + 8 x - 4 = 0

x^{3} - x^{2} + 3 x + 5 = 0

5 s^{3} + 7 s + 6.4 = 0

What are the solutions to the equation solvefor x,x(x+1)(x+2)=-1 ?
The solutions to the equation solvefor x,x(x+1)(x+2)=-1 are x\approx-2.32471…
Find the zeros of solvefor x,x(x+1)(x+2)=-1
The zeros of solvefor x,x(x+1)(x+2)=-1 are x\approx-2.32471…