What are the solutions to the equation 4y-y^3=0 ?

The solutions to the equation 4y-y^3=0 are y=0,y=-2,y=2

Find the zeros of 4y-y^3=0

The zeros of 4y-y^3=0 are y=0,y=-2,y=2

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4 y - y^{3} = 0

y = 0, y = - 2, y = 2

Solution steps

4 y - y^{3} = 0

Factor

4 y - y^{3} : - y (y + 2) (y - 2)

- y (y + 2) (y - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y + 2 = 0 or y - 2 = 0

Solve

y + 2 = 0 : y = - 2

Solve

y - 2 = 0 : y = 2

The solutions are

y = 0, y = - 2, y = 2

19 = 0.074 t^{4}

4 x^{4} - 5 x^{2} = - 4

x^{3} + x - 7 = 0

x^{4} + x^{2} + 2 x + 6 = 0

b (2) = x^{3} + 3

What are the solutions to the equation 4y-y^3=0 ?
The solutions to the equation 4y-y^3=0 are y=0,y=-2,y=2
Find the zeros of 4y-y^3=0
The zeros of 4y-y^3=0 are y=0,y=-2,y=2