What are the solutions to the equation 7x=x^6+5(3x+3)-x ?

The solutions to the equation 7x=x^6+5(3x+3)-x are No Solution for x\in\mathbb{R}

Find the zeros of 7x=x^6+5(3x+3)-x

The zeros of 7x=x^6+5(3x+3)-x are No Solution for x\in\mathbb{R}

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7 x = x^{6} + 5 (3 x + 3) - x

No Solution for x \in R

Solution steps

7 x = x^{6} + 5 (3 x + 3) - x

Expand

x^{6} + 5 (3 x + 3) - x : x^{6} + 14 x + 15

7 x = x^{6} + 14 x + 15

Switch sides

x^{6} + 14 x + 15 = 7 x

Move

7 x

to the left side

x^{6} + 7 x + 15 = 0

Find one solution for

x^{6} + 7 x + 15 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

x^{3} - 2 x = 1

R, T^{2} = R^{3}

(x - 1)^{4} + 2 (x - 1)^{2} - 3 = 0

(6 x + 7)^{2} (3 x + 4) (x + 1) = 6

x^{5} - x^{4} - 3 x^{3} + 5 x^{2} - 2 x = 0

What are the solutions to the equation 7x=x^6+5(3x+3)-x ?
The solutions to the equation 7x=x^6+5(3x+3)-x are No Solution for x\in\mathbb{R}
Find the zeros of 7x=x^6+5(3x+3)-x
The zeros of 7x=x^6+5(3x+3)-x are No Solution for x\in\mathbb{R}