What are the solutions to the equation m^3-4m^2+6m-4=0 ?

The solutions to the equation m^3-4m^2+6m-4=0 are m=2,m=1+i,m=1-i

Find the zeros of m^3-4m^2+6m-4=0

The zeros of m^3-4m^2+6m-4=0 are m=2,m=1+i,m=1-i

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m^{3} - 4 m^{2} + 6 m - 4 = 0

m = 2, m = 1 + i, m = 1 - i

Solution steps

m^{3} - 4 m^{2} + 6 m - 4 = 0

Factor

m^{3} - 4 m^{2} + 6 m - 4 : (m - 2) (m^{2} - 2 m + 2)

(m - 2) (m^{2} - 2 m + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 2 = 0 or m^{2} - 2 m + 2 = 0

Solve

m - 2 = 0 : m = 2

Solve

m^{2} - 2 m + 2 = 0 : m = 1 + i, m = 1 - i

The solutions are

m = 2, m = 1 + i, m = 1 - i

s^{3} + 3 s^{2} + 2 s - 10 = 0

- 2 x^{4} + 7 = 3 x + 1

3 x^{3} - 27 x^{2} = 0

x, 135 = 5 x^{3}

y, x = (y - 2)^{3} + 1

What are the solutions to the equation m^3-4m^2+6m-4=0 ?
The solutions to the equation m^3-4m^2+6m-4=0 are m=2,m=1+i,m=1-i
Find the zeros of m^3-4m^2+6m-4=0
The zeros of m^3-4m^2+6m-4=0 are m=2,m=1+i,m=1-i