What are the solutions to the equation 2y^5-7y^4+12y^3+8y^2=0 ?

The solutions to the equation 2y^5-7y^4+12y^3+8y^2=0 are y=0,y=-1/2 ,y=2+2i,y=2-2i

Find the zeros of 2y^5-7y^4+12y^3+8y^2=0

The zeros of 2y^5-7y^4+12y^3+8y^2=0 are y=0,y=-1/2 ,y=2+2i,y=2-2i

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2 y^{5} - 7 y^{4} + 12 y^{3} + 8 y^{2} = 0

y = 0, y = - \frac{1}{2}, y = 2 + 2 i, y = 2 - 2 i

Solution steps

2 y^{5} - 7 y^{4} + 12 y^{3} + 8 y^{2} = 0

Factor

2 y^{5} - 7 y^{4} + 12 y^{3} + 8 y^{2} : y^{2} (2 y + 1) (y^{2} - 4 y + 8)

y^{2} (2 y + 1) (y^{2} - 4 y + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 2 y + 1 = 0 or y^{2} - 4 y + 8 = 0

Solve

2 y + 1 = 0 : y = - \frac{1}{2}

Solve

y^{2} - 4 y + 8 = 0 : y = 2 + 2 i, y = 2 - 2 i

The solutions are

y = 0, y = - \frac{1}{2}, y = 2 + 2 i, y = 2 - 2 i

4 (x + 2) = 2 (x^{5}) + 4

d = (x^{1} - x^{2})^{2}

5 P^{5} = \frac{5 !}{( 5 - 5 ) !}

2 x^{4} = - 6 x^{3} + 20 x^{2}

4 z^{5} - 10 z^{2} = 0

What are the solutions to the equation 2y^5-7y^4+12y^3+8y^2=0 ?
The solutions to the equation 2y^5-7y^4+12y^3+8y^2=0 are y=0,y=-1/2 ,y=2+2i,y=2-2i
Find the zeros of 2y^5-7y^4+12y^3+8y^2=0
The zeros of 2y^5-7y^4+12y^3+8y^2=0 are y=0,y=-1/2 ,y=2+2i,y=2-2i