What are the solutions to the equation x^3-28x+48=0 ?

The solutions to the equation x^3-28x+48=0 are x=2,x=4,x=-6

Find the zeros of x^3-28x+48=0

The zeros of x^3-28x+48=0 are x=2,x=4,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 28 x + 48 = 0

x = 2, x = 4, x = - 6

Solution steps

x^{3} - 28 x + 48 = 0

Factor

x^{3} - 28 x + 48 : (x - 2) (x - 4) (x + 6)

(x - 2) (x - 4) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0 or x + 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

Solve

x + 6 = 0 : x = - 6

The solutions are

x = 2, x = 4, x = - 6

r^{3} - 2 r^{2} + r = 0

y, x = 7 + (2 y + 1)^{3}

x^{4} + x^{3} + x + 1 = 0

6 x^{5} - 6 x^{4} = 0

895 = 5 x^{3}

What are the solutions to the equation x^3-28x+48=0 ?
The solutions to the equation x^3-28x+48=0 are x=2,x=4,x=-6
Find the zeros of x^3-28x+48=0
The zeros of x^3-28x+48=0 are x=2,x=4,x=-6