What are the solutions to the equation r^3=-1 ?

The solutions to the equation r^3=-1 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i

Find the zeros of r^3=-1

The zeros of r^3=-1 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{3} = - 1

r = - 1, r = \frac{1}{2} - \frac{3}{2} i, r = \frac{1}{2} + \frac{3}{2} i

Solution steps

r^{3} = - 1

For

x^{3} = f (a)

the solutions are

Simplify

r = - 1, r = \frac{1}{2} - \frac{3}{2} i, r = \frac{1}{2} + \frac{3}{2} i

x^{5} = x + 2

6 y^{4} = 7 - 3 y^{2}

(x^{2} + 1) (2 x - 2) = 0

4 \cdot (x^{4} + 1) = 5 x^{2}

r^{3} - 3 r^{2} + 2 r - 1 = 0

What are the solutions to the equation r^3=-1 ?
The solutions to the equation r^3=-1 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i
Find the zeros of r^3=-1
The zeros of r^3=-1 are r=-1,r= 1/2-(sqrt(3))/2 i,r= 1/2+(sqrt(3))/2 i