What are the solutions to the equation x^2(4x+5)-(4x+5)=0 ?

The solutions to the equation x^2(4x+5)-(4x+5)=0 are x=-1,x=1,x=-5/4

Find the zeros of x^2(4x+5)-(4x+5)=0

The zeros of x^2(4x+5)-(4x+5)=0 are x=-1,x=1,x=-5/4

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x^{2} (4 x + 5) - (4 x + 5) = 0

x = - 1, x = 1, x = - \frac{5}{4}

Decimal Notation

x = - 1, x = 1, x = - 1.25

Solution steps

x^{2} (4 x + 5) - (4 x + 5) = 0

Factor

x^{2} (4 x + 5) - (4 x + 5) : (x + 1) (x - 1) (4 x + 5)

(x + 1) (x - 1) (4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or 4 x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

The solutions are

x = - 1, x = 1, x = - \frac{5}{4}

x^{3} - 11 x^{2} - 11 x + 121 = 0

x^{3} + 5 x^{2} - 36 x - 180 = 0

4 x^{3} - 2 x^{2} + 6 x - 3 = 0

8 x^{4} + 27 = 0

x^{3} - 2 x^{2} - 35 x = 0

What are the solutions to the equation x^2(4x+5)-(4x+5)=0 ?
The solutions to the equation x^2(4x+5)-(4x+5)=0 are x=-1,x=1,x=-5/4
Find the zeros of x^2(4x+5)-(4x+5)=0
The zeros of x^2(4x+5)-(4x+5)=0 are x=-1,x=1,x=-5/4