What are the solutions to the equation 4x(5x^2-3)=0 ?

The solutions to the equation 4x(5x^2-3)=0 are x=0,x=-sqrt(3/5),x=sqrt(3/5)

Find the zeros of 4x(5x^2-3)=0

The zeros of 4x(5x^2-3)=0 are x=0,x=-sqrt(3/5),x=sqrt(3/5)

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4 x (5 x^{2} - 3) = 0

x = 0, x = - \frac{3}{5}, x = \frac{3}{5}

Decimal Notation

x = 0, x = - 0.77459 \dots, x = 0.77459 \dots

Solution steps

4 x (5 x^{2} - 3) = 0

Factor

4 x (5 x^{2} - 3) : 4 x (5 x + 3) (5 x - 3)

4 x (5 x + 3) (5 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x + 3 = 0 or 5 x - 3 = 0

Solve

5 x + 3 = 0 : x = - \frac{3}{5}

Solve

5 x - 3 = 0 : x = \frac{3}{5}

The solutions are

x = 0, x = - \frac{3}{5}, x = \frac{3}{5}

20 x = x^{2} (x) + 36 x - 2 x (x) (x)

y, y^{2} - y^{4} = x

x^{4} - 3 x + 4 = 0

2 x^{3} - 3 x^{2} - 2 x + 3 = 0

\frac{1}{3} x^{4} = 27

What are the solutions to the equation 4x(5x^2-3)=0 ?
The solutions to the equation 4x(5x^2-3)=0 are x=0,x=-sqrt(3/5),x=sqrt(3/5)
Find the zeros of 4x(5x^2-3)=0
The zeros of 4x(5x^2-3)=0 are x=0,x=-sqrt(3/5),x=sqrt(3/5)