What are the solutions to the equation 3t^3+4t^2-5t-2=0 ?

The solutions to the equation 3t^3+4t^2-5t-2=0 are t=1,t=-1/3 ,t=-2

Find the zeros of 3t^3+4t^2-5t-2=0

The zeros of 3t^3+4t^2-5t-2=0 are t=1,t=-1/3 ,t=-2

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3 t^{3} + 4 t^{2} - 5 t - 2 = 0

t = 1, t = - \frac{1}{3}, t = - 2

Decimal Notation

t = 1, t = - 0.33333 \dots, t = - 2

Solution steps

3 t^{3} + 4 t^{2} - 5 t - 2 = 0

Factor

3 t^{3} + 4 t^{2} - 5 t - 2 : (t - 1) (3 t + 1) (t + 2)

(t - 1) (3 t + 1) (t + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t - 1 = 0 or 3 t + 1 = 0 or t + 2 = 0

Solve

t - 1 = 0 : t = 1

Solve

3 t + 1 = 0 : t = - \frac{1}{3}

Solve

t + 2 = 0 : t = - 2

The solutions are

t = 1, t = - \frac{1}{3}, t = - 2

9 x^{5} = 54

x, x^{3} - 3 x^{2} + x - 3 = 0

2.9 = b^{3}

x^{8} - 13 x^{4} + 36 = 0

- 6 x^{3} + 15 x^{2} - 36 x + 15 = 0

What are the solutions to the equation 3t^3+4t^2-5t-2=0 ?
The solutions to the equation 3t^3+4t^2-5t-2=0 are t=1,t=-1/3 ,t=-2
Find the zeros of 3t^3+4t^2-5t-2=0
The zeros of 3t^3+4t^2-5t-2=0 are t=1,t=-1/3 ,t=-2