What are the solutions to the equation 6x^3-x^2=12x ?

The solutions to the equation 6x^3-x^2=12x are x=0,x=-4/3 ,x= 3/2

Find the zeros of 6x^3-x^2=12x

The zeros of 6x^3-x^2=12x are x=0,x=-4/3 ,x= 3/2

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6 x^{3} - x^{2} = 12 x

x = 0, x = - \frac{4}{3}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 1.33333 \dots, x = 1.5

Solution steps

6 x^{3} - x^{2} = 12 x

Move

12 x

to the left side

6 x^{3} - x^{2} - 12 x = 0

Factor

6 x^{3} - x^{2} - 12 x : x (3 x + 4) (2 x - 3)

x (3 x + 4) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 4 = 0 or 2 x - 3 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - \frac{4}{3}, x = \frac{3}{2}

- 4 y^{3} + 300 y^{2} - 250000 = 0

16 x^{4} - 4 x^{2} + 1 = 0

x^{10} + 5 x^{5} + 6 = 0

y, x = y^{11}

0 = 36 x - x^{3}

What are the solutions to the equation 6x^3-x^2=12x ?
The solutions to the equation 6x^3-x^2=12x are x=0,x=-4/3 ,x= 3/2
Find the zeros of 6x^3-x^2=12x
The zeros of 6x^3-x^2=12x are x=0,x=-4/3 ,x= 3/2