What are the solutions to the equation 12x^3-23x^2-3x+2=0 ?

The solutions to the equation 12x^3-23x^2-3x+2=0 are x=2,x= 1/4 ,x=-1/3

Find the zeros of 12x^3-23x^2-3x+2=0

The zeros of 12x^3-23x^2-3x+2=0 are x=2,x= 1/4 ,x=-1/3

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12 x^{3} - 23 x^{2} - 3 x + 2 = 0

x = 2, x = \frac{1}{4}, x = - \frac{1}{3}

Decimal Notation

x = 2, x = 0.25, x = - 0.33333 \dots

Solution steps

12 x^{3} - 23 x^{2} - 3 x + 2 = 0

Factor

12 x^{3} - 23 x^{2} - 3 x + 2 : (x - 2) (4 x - 1) (3 x + 1)

(x - 2) (4 x - 1) (3 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 4 x - 1 = 0 or 3 x + 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solutions are

x = 2, x = \frac{1}{4}, x = - \frac{1}{3}

∣ x + 2 ∣ > 5

9 x^{2} - 72 x + 144

x^{2} - 3 x - 1 = 4

\frac{3}{4} y = 24

1 - 0.4 x \leq 3.4 - 0.6 x

What are the solutions to the equation 12x^3-23x^2-3x+2=0 ?
The solutions to the equation 12x^3-23x^2-3x+2=0 are x=2,x= 1/4 ,x=-1/3
Find the zeros of 12x^3-23x^2-3x+2=0
The zeros of 12x^3-23x^2-3x+2=0 are x=2,x= 1/4 ,x=-1/3