What are the solutions to the equation t^3-2t^2-123t+540=0 ?

The solutions to the equation t^3-2t^2-123t+540=0 are t=5,t=9,t=-12

Find the zeros of t^3-2t^2-123t+540=0

The zeros of t^3-2t^2-123t+540=0 are t=5,t=9,t=-12

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t^{3} - 2 t^{2} - 123 t + 540 = 0

t = 5, t = 9, t = - 12

Solution steps

t^{3} - 2 t^{2} - 123 t + 540 = 0

Factor

t^{3} - 2 t^{2} - 123 t + 540 : (t - 5) (t - 9) (t + 12)

(t - 5) (t - 9) (t + 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t - 5 = 0 or t - 9 = 0 or t + 12 = 0

Solve

t - 5 = 0 : t = 5

Solve

t - 9 = 0 : t = 9

Solve

t + 12 = 0 : t = - 12

The solutions are

t = 5, t = 9, t = - 12

114 s^{5} = 1.34 \cdot 10 - 34

x^{3} + 3 x - 4 = 5

(x) = (x - 5) (x + 2) (x - 4)

2840 = 1000 \cdot (1 + x)^{5}

x^{4} + 2 x^{3} - 13 x^{2} - 14 x = - 24

What are the solutions to the equation t^3-2t^2-123t+540=0 ?
The solutions to the equation t^3-2t^2-123t+540=0 are t=5,t=9,t=-12
Find the zeros of t^3-2t^2-123t+540=0
The zeros of t^3-2t^2-123t+540=0 are t=5,t=9,t=-12