What are the solutions to the equation (1-x)*(2-x)*(3-x)=0 ?

The solutions to the equation (1-x)*(2-x)*(3-x)=0 are x=1,x=2,x=3

Find the zeros of (1-x)*(2-x)*(3-x)=0

The zeros of (1-x)*(2-x)*(3-x)=0 are x=1,x=2,x=3

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(1 - x) \cdot (2 - x) \cdot (3 - x) = 0

x = 1, x = 2, x = 3

Solution steps

(1 - x) (2 - x) (3 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 - x = 0 or 2 - x = 0 or 3 - x = 0

Solve

1 - x = 0 : x = 1

Solve

2 - x = 0 : x = 2

Solve

3 - x = 0 : x = 3

The solutions are

x = 1, x = 2, x = 3

x^{3} + x - 9 = 0

- x^{2} + x^{3} + 5 = 5 x

- 4 x^{3} + 24 x^{2} - 36 x = 0

4 x^{3} + 5 x^{2} + 12 x + 15 = 0

x^{4} - 8 x^{2} - 16 = 0

What are the solutions to the equation (1-x)*(2-x)*(3-x)=0 ?
The solutions to the equation (1-x)*(2-x)*(3-x)=0 are x=1,x=2,x=3
Find the zeros of (1-x)*(2-x)*(3-x)=0
The zeros of (1-x)*(2-x)*(3-x)=0 are x=1,x=2,x=3