What are the solutions to the equation v^3=27 ?

The solutions to the equation v^3=27 are v=3,v=-3/2+(3sqrt(3))/2 i,v=-3/2-(3sqrt(3))/2 i

Find the zeros of v^3=27

The zeros of v^3=27 are v=3,v=-3/2+(3sqrt(3))/2 i,v=-3/2-(3sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{3} = 27

v = 3, v = - \frac{3}{2} + \frac{3 3}{2} i, v = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

v^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

v = 3, v = - \frac{3}{2} + \frac{3 3}{2} i, v = - \frac{3}{2} - \frac{3 3}{2} i

x^{3} = 3937.5

- 2 x^{3} - x = - 6

z^{6} - (3 - 2 i) z^{3} + 2 - 2 i = 0

4 (x^{2} - x)^{2} - 11 (x^{2} - x) + 6 = 0

5 y^{3} + 33 y^{2} = 14 y

What are the solutions to the equation v^3=27 ?
The solutions to the equation v^3=27 are v=3,v=-3/2+(3sqrt(3))/2 i,v=-3/2-(3sqrt(3))/2 i
Find the zeros of v^3=27
The zeros of v^3=27 are v=3,v=-3/2+(3sqrt(3))/2 i,v=-3/2-(3sqrt(3))/2 i