What are the solutions to the equation 77=16*(1+r)^4 ?

The solutions to the equation 77=16*(1+r)^4 are r=(\sqrt[4]{77})/2-1,r=-(\sqrt[4]{77})/2-1

Find the zeros of 77=16*(1+r)^4

The zeros of 77=16*(1+r)^4 are r=(\sqrt[4]{77})/2-1,r=-(\sqrt[4]{77})/2-1

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77 = 16 \cdot (1 + r)^{4}

Solution steps

77 = 16 (1 + r)^{4}

Switch sides

16 (1 + r)^{4} = 77

Divide both sides by

16

(1 + r)^{4} = \frac{77}{16}

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

- 9 = t^{8} - 12

x^{3} - x^{2} - 11 x + 3 = 0

2 x^{3} - x^{2} - x + 1 = 0

(x - 2)^{3} = 4

2 x^{3} - 6 x^{2} + 8 = 0

What are the solutions to the equation 77=16*(1+r)^4 ?
The solutions to the equation 77=16*(1+r)^4 are r=(\sqrt[4]{77})/2-1,r=-(\sqrt[4]{77})/2-1
Find the zeros of 77=16*(1+r)^4
The zeros of 77=16*(1+r)^4 are r=(\sqrt[4]{77})/2-1,r=-(\sqrt[4]{77})/2-1