What are the solutions to the equation x^3-5x+6=2*2 ?

The solutions to the equation x^3-5x+6=2*2 are x=2,x=-1+sqrt(2),x=-1-sqrt(2)

Find the zeros of x^3-5x+6=2*2

The zeros of x^3-5x+6=2*2 are x=2,x=-1+sqrt(2),x=-1-sqrt(2)

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x^{3} - 5 x + 6 = 2 \cdot 2

x = 2, x = - 1 + 2, x = - 1 - 2

Solution steps

x^{3} - 5 x + 6 = 2 \cdot 2

Expand

2 \cdot 2 : 4

x^{3} - 5 x + 6 = 4

Move

4

to the left side

x^{3} - 5 x + 2 = 0

Factor

x^{3} - 5 x + 2 : (x - 2) (x^{2} + 2 x - 1)

(x - 2) (x^{2} + 2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 2 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x - 1 = 0 : x = - 1 + 2, x = - 1 - 2

The solutions are

x = 2, x = - 1 + 2, x = - 1 - 2

2 x^{3} + 3 x^{2} - 18 x - 27 = 0

81 x^{8} - 25 x^{4} = 0

x, x^{3} + 9 x = 0

0.5 g^{9} + 3.5 g = 11 - 0.5 g

x, x^{2} (x^{3}) = y^{10}

What are the solutions to the equation x^3-5x+6=2*2 ?
The solutions to the equation x^3-5x+6=2*2 are x=2,x=-1+sqrt(2),x=-1-sqrt(2)
Find the zeros of x^3-5x+6=2*2
The zeros of x^3-5x+6=2*2 are x=2,x=-1+sqrt(2),x=-1-sqrt(2)