What are the solutions to the equation x^4=-(-x^2)^2 ?

The solutions to the equation x^4=-(-x^2)^2 are x=0

Find the zeros of x^4=-(-x^2)^2

The zeros of x^4=-(-x^2)^2 are x=0

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x^{4} = - (- x^{2})^{2}

x = 0

Solution steps

x^{4} = - (- x^{2})^{2}

Expand

- (- x^{2})^{2} : - x^{4}

x^{4} = - x^{4}

Move

x^{4}

to the left side

2 x^{4} = 0

Divide both sides by

2

x^{4} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0

The solution is

x = 0

(x^{4})^{2} = 16 - 15 (x^{2})^{2}

x^{4} - x^{3} - x^{2} - 1 = 0

- x^{4} + x^{3} + 2 x^{2} - 1 = 0

2 x^{3} + 0 x^{2} + 7 x - 8 = 0

a^{4} - 10 a^{2} = - 21

What are the solutions to the equation x^4=-(-x^2)^2 ?
The solutions to the equation x^4=-(-x^2)^2 are x=0
Find the zeros of x^4=-(-x^2)^2
The zeros of x^4=-(-x^2)^2 are x=0