What are the solutions to the equation (x-3)(x+5)(x-7)(x+1)=0 ?

The solutions to the equation (x-3)(x+5)(x-7)(x+1)=0 are x=3,x=-5,x=7,x=-1

Find the zeros of (x-3)(x+5)(x-7)(x+1)=0

The zeros of (x-3)(x+5)(x-7)(x+1)=0 are x=3,x=-5,x=7,x=-1

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(x - 3) (x + 5) (x - 7) (x + 1) = 0

x = 3, x = - 5, x = 7, x = - 1

Solution steps

(x - 3) (x + 5) (x - 7) (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 5 = 0 or x - 7 = 0 or x + 1 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 5 = 0 : x = - 5

Solve

x - 7 = 0 : x = 7

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 3, x = - 5, x = 7, x = - 1

y^{4} y + 1 = 13

2 x^{3} + 7 = 25

x^{3} + 2 x^{2} = 15 x

14 x (11 x - 2) (4 x + 13) = 0

(2 x - 1)^{3} = 0

What are the solutions to the equation (x-3)(x+5)(x-7)(x+1)=0 ?
The solutions to the equation (x-3)(x+5)(x-7)(x+1)=0 are x=3,x=-5,x=7,x=-1
Find the zeros of (x-3)(x+5)(x-7)(x+1)=0
The zeros of (x-3)(x+5)(x-7)(x+1)=0 are x=3,x=-5,x=7,x=-1