What are the solutions to the equation x^3+5x^2+2x-8=x^2+3x-4 ?

The solutions to the equation x^3+5x^2+2x-8=x^2+3x-4 are x=-4,x=-1,x=1

Find the zeros of x^3+5x^2+2x-8=x^2+3x-4

The zeros of x^3+5x^2+2x-8=x^2+3x-4 are x=-4,x=-1,x=1

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x^{3} + 5 x^{2} + 2 x - 8 = x^{2} + 3 x - 4

x = - 4, x = - 1, x = 1

Solution steps

x^{3} + 5 x^{2} + 2 x - 8 = x^{2} + 3 x - 4

Move

4

to the left side

x^{3} + 5 x^{2} + 2 x - 4 = x^{2} + 3 x

Move

3 x

to the left side

x^{3} + 5 x^{2} - x - 4 = x^{2}

Move

x^{2}

to the left side

x^{3} + 4 x^{2} - x - 4 = 0

Factor

x^{3} + 4 x^{2} - x - 4 : (x + 4) (x + 1) (x - 1)

(x + 4) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 4, x = - 1, x = 1

(3 w - 21) (w^{2} + 9 w + 20) = 0

y, 34 x - y^{3} = 23 x - 9

0 = x^{3} + x + 1

2 x^{4} - 4 x^{3} - 2 x^{2} = 0

4 x^{3} + 3 = 0

What are the solutions to the equation x^3+5x^2+2x-8=x^2+3x-4 ?
The solutions to the equation x^3+5x^2+2x-8=x^2+3x-4 are x=-4,x=-1,x=1
Find the zeros of x^3+5x^2+2x-8=x^2+3x-4
The zeros of x^3+5x^2+2x-8=x^2+3x-4 are x=-4,x=-1,x=1