What are the solutions to the equation (12-3x)*(2x-1)x=0 ?

The solutions to the equation (12-3x)*(2x-1)x=0 are x=4,x= 1/2 ,x=0

Find the zeros of (12-3x)*(2x-1)x=0

The zeros of (12-3x)*(2x-1)x=0 are x=4,x= 1/2 ,x=0

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(12 - 3 x) \cdot (2 x - 1) x = 0

x = 4, x = \frac{1}{2}, x = 0

Decimal Notation

x = 4, x = 0.5, x = 0

Solution steps

(12 - 3 x) (2 x - 1) x = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

12 - 3 x = 0 or 2 x - 1 = 0 or x = 0

Solve

12 - 3 x = 0 : x = 4

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 4, x = \frac{1}{2}, x = 0

x^{3} - 0.75 x - 0.25 = 0

- λ^{3} + 5 λ^{2} = 0

525 = 5 x^{3}

27 x^{4} - 7 x^{3} + 14 = 0

x, (x + y)^{3} = 64

What are the solutions to the equation (12-3x)*(2x-1)x=0 ?
The solutions to the equation (12-3x)*(2x-1)x=0 are x=4,x= 1/2 ,x=0
Find the zeros of (12-3x)*(2x-1)x=0
The zeros of (12-3x)*(2x-1)x=0 are x=4,x= 1/2 ,x=0