What are the solutions to the equation (4x^4)+5=(4-4) ?

The solutions to the equation (4x^4)+5=(4-4) are

Find the zeros of (4x^4)+5=(4-4)

The zeros of (4x^4)+5=(4-4) are

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(4 x^{4}) + 5 = (4 - 4)

Solution steps

(4 x^{4}) + 5 = (4 - 4)

Refine

4 x^{4} + 5 = 0

Move

5

to the right side

4 x^{4} = - 5

Divide both sides by

4

x^{4} = - \frac{5}{4}

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = - \frac{5}{4}

Solve

u^{2} = - \frac{5}{4} : u = \frac{5}{2} i, u = - \frac{5}{2} i

u = \frac{5}{2} i, u = - \frac{5}{2} i

Substitute back

u = x^{2},

solve for

x

Solve

The solutions are

x^{3} + 8 x^{2} + 19 x + 12 = 0

40000 = 15000 (1 + x)^{5}

x, x^{4} - 10 x^{2} + 29 = 8

(x^{2} - 4)^{2} = (x + 4)^{2} + 32

2 x^{3} + 7 x^{2} = 15 x

What are the solutions to the equation (4x^4)+5=(4-4) ?
The solutions to the equation (4x^4)+5=(4-4) are
Find the zeros of (4x^4)+5=(4-4)
The zeros of (4x^4)+5=(4-4) are