What is factor 6u^2*(2u-5)2-12u^2*(2u-5)*(u+5) ?

The solution to factor 6u^2*(2u-5)2-12u^2*(2u-5)*(u+5) is -12u^2(2u-5)(u+4)

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factor 6u^2(2u-5)2-12u^2(2u-5)*(u+5)

factor

6 u^{2} \cdot (2 u - 5) 2 - 12 u^{2} \cdot (2 u - 5) \cdot (u + 5)

- 12 u^{2} (2 u - 5) (u + 4)

Solution steps

6 u^{2} (2 u - 5) \cdot 2 - 12 u^{2} (2 u - 5) (u + 5)

Factor out common term

6 \cdot 2 u^{2} (2 u - 5) : 6 \cdot 2 u^{2} (2 u - 5) (1 - (u + 5))

= 6 \cdot 2 u^{2} (2 u - 5) (1 - (u + 5))

Simplify

6 \cdot 2 u^{2} (2 u - 5) (1 - (u + 5)) : 12 u^{2} (2 u - 5) (- u - 4)

= 12 u^{2} (2 u - 5) (- u - 4)

Factor

- u - 4 : - (u + 4)

= 12 u^{2} (2 u - 5) (- (u + 4))

Apply rule:

a (- b) = - ab

12 u^{2} (2 u - 5) (- (u + 4)) = - 12 u^{2} (2 u - 5) (u + 4)

= - 12 u^{2} (2 u - 5) (u + 4)

∣ 2 x + 1 ∣ < 4

- 2 x + 4 = 16

x^{2} + 10 x + 25 = 0

\frac{1}{4} x - 5 = 27

\frac{0}{- 1}

What is factor 6u^2*(2u-5)2-12u^2*(2u-5)*(u+5) ?
The solution to factor 6u^2*(2u-5)2-12u^2*(2u-5)*(u+5) is -12u^2(2u-5)(u+4)