What are the solutions to the equation x^3-8x^2+9x+18=0 ?

The solutions to the equation x^3-8x^2+9x+18=0 are x=-1,x=3,x=6

Find the zeros of x^3-8x^2+9x+18=0

The zeros of x^3-8x^2+9x+18=0 are x=-1,x=3,x=6

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x^{3} - 8 x^{2} + 9 x + 18 = 0

x = - 1, x = 3, x = 6

Solution steps

x^{3} - 8 x^{2} + 9 x + 18 = 0

Factor

x^{3} - 8 x^{2} + 9 x + 18 : (x + 1) (x - 3) (x - 6)

(x + 1) (x - 3) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0 or x - 6 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

Solve

x - 6 = 0 : x = 6

The solutions are

x = - 1, x = 3, x = 6

- 15 y^{4} = (D) (3 y^{2})

x^{6} + x^{3} - 42 = 0

6 y^{2} + 9 y = 15 y^{3}

x^{3} + 3 x^{2} - 4 x + 12 = 0

5 x^{3} + 30 x^{2} + 45 = 0

What are the solutions to the equation x^3-8x^2+9x+18=0 ?
The solutions to the equation x^3-8x^2+9x+18=0 are x=-1,x=3,x=6
Find the zeros of x^3-8x^2+9x+18=0
The zeros of x^3-8x^2+9x+18=0 are x=-1,x=3,x=6