What are the solutions to the equation -x^4-4x^3-5x^2-2=0 ?

The solutions to the equation -x^4-4x^3-5x^2-2=0 are No Solution for x\in\mathbb{R}

Find the zeros of -x^4-4x^3-5x^2-2=0

The zeros of -x^4-4x^3-5x^2-2=0 are No Solution for x\in\mathbb{R}

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- x^{4} - 4 x^{3} - 5 x^{2} - 2 = 0

No Solution for x \in R

Solution steps

- x^{4} - 4 x^{3} - 5 x^{2} - 2 = 0

Find one solution for

- x^{4} - 4 x^{3} - 5 x^{2} - 2 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

f^{3} = f^{3} - 1 + f^{3} - 3

x, f (a + b) f = x^{4}

2 (3 x^{4}) = (2 x^{3}) (2 x^{4})

x^{23} - 2 x^{13} - 15 = 0

x^{3} - 16 x^{2} + 16 x + 6 = 0

What are the solutions to the equation -x^4-4x^3-5x^2-2=0 ?
The solutions to the equation -x^4-4x^3-5x^2-2=0 are No Solution for x\in\mathbb{R}
Find the zeros of -x^4-4x^3-5x^2-2=0
The zeros of -x^4-4x^3-5x^2-2=0 are No Solution for x\in\mathbb{R}