What are the solutions to the equation x^3+13x=4x^2 ?

The solutions to the equation x^3+13x=4x^2 are x=0,x=2+3i,x=2-3i

Find the zeros of x^3+13x=4x^2

The zeros of x^3+13x=4x^2 are x=0,x=2+3i,x=2-3i

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x^{3} + 13 x = 4 x^{2}

x = 0, x = 2 + 3 i, x = 2 - 3 i

Solution steps

x^{3} + 13 x = 4 x^{2}

Move

4 x^{2}

to the left side

x^{3} + 13 x - 4 x^{2} = 0

Factor

x^{3} + 13 x - 4 x^{2} : x (x^{2} - 4 x + 13)

x (x^{2} - 4 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 4 x + 13 = 0

Solve

x^{2} - 4 x + 13 = 0 : x = 2 + 3 i, x = 2 - 3 i

The solutions are

x = 0, x = 2 + 3 i, x = 2 - 3 i

8 = a^{4}

(x^{2} - 7)^{2} + 4 (x^{2} - 7) - 5 = 0

- 2 x^{4} + 5 = 13

x^{12} - 1 = 4

7 x^{3} - 9 x^{2} - 7 x = - 9

What are the solutions to the equation x^3+13x=4x^2 ?
The solutions to the equation x^3+13x=4x^2 are x=0,x=2+3i,x=2-3i
Find the zeros of x^3+13x=4x^2
The zeros of x^3+13x=4x^2 are x=0,x=2+3i,x=2-3i