What are the solutions to the equation 0=-x^3+4*x ?

The solutions to the equation 0=-x^3+4*x are x=0,x=-2,x=2

Find the zeros of 0=-x^3+4*x

The zeros of 0=-x^3+4*x are x=0,x=-2,x=2

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0 = - x^{3} + 4 \cdot x

x = 0, x = - 2, x = 2

Solution steps

0 = - x^{3} + 4 x

Switch sides

- x^{3} + 4 x = 0

Factor

- x^{3} + 4 x : - x (x + 2) (x - 2)

- x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

x^{3} + 4 x + 3 = 0

x^{3} + 4 x^{2} - 20 x = 80

4 x^{3} + x + 3 = 0

x^{5} + 64 x^{2} = 0

x, 5 x^{3} - 8 = 2 y^{2}

What are the solutions to the equation 0=-x^3+4*x ?
The solutions to the equation 0=-x^3+4*x are x=0,x=-2,x=2
Find the zeros of 0=-x^3+4*x
The zeros of 0=-x^3+4*x are x=0,x=-2,x=2