What are the solutions to the equation -100a^2+20a-1=0 ?

The solutions to the equation -100a^2+20a-1=0 are a= 1/10

Find the zeros of -100a^2+20a-1=0

The zeros of -100a^2+20a-1=0 are a= 1/10

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- 100 a^{2} + 20 a - 1 = 0

a = \frac{1}{10}

Decimal Notation

a = 0.1

Solution steps

- 100 a^{2} + 20 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 100 ) ( - 1 )}{2 ( - 100 )}

2 0^{2} - 4 (- 100) (- 1) = 0

a_{1, 2} = \frac{- 20 \pm 0}{2 ( - 100 )}

a = \frac{- 20}{2 ( - 100 )}

\frac{- 20}{2 ( - 100 )} = \frac{1}{10}

a = \frac{1}{10}

The solution to the quadratic equation is:

a = \frac{1}{10}

\frac{x + 3}{8} = \frac{5}{4}

- 8 x > - 12

A = 5000 (1 + \frac{0.08}{2})^{10}

4 (k + 3) = 3 (k - 2)

ln (3) = x

What are the solutions to the equation -100a^2+20a-1=0 ?
The solutions to the equation -100a^2+20a-1=0 are a= 1/10
Find the zeros of -100a^2+20a-1=0
The zeros of -100a^2+20a-1=0 are a= 1/10