What are the solutions to the equation 0=x^3-6x^2+32 ?

The solutions to the equation 0=x^3-6x^2+32 are x=-2,x=4

Find the zeros of 0=x^3-6x^2+32

The zeros of 0=x^3-6x^2+32 are x=-2,x=4

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0 = x^{3} - 6 x^{2} + 32

x = - 2, x = 4

Solution steps

0 = x^{3} - 6 x^{2} + 32

Switch sides

x^{3} - 6 x^{2} + 32 = 0

Factor

x^{3} - 6 x^{2} + 32 : (x + 2) (x - 4)^{2}

(x + 2) (x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 4 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 2, x = 4

x, y = x^{3} - 1

3 \cdot (x^{3} - 1) = - 27

(x - 2)^{3} = - x + 4

220000 = 100000 \cdot (1 + x)^{3}

x, f = 10 + x^{3} f (27)

What are the solutions to the equation 0=x^3-6x^2+32 ?
The solutions to the equation 0=x^3-6x^2+32 are x=-2,x=4
Find the zeros of 0=x^3-6x^2+32
The zeros of 0=x^3-6x^2+32 are x=-2,x=4