What are the solutions to the equation 0=24x^3+2x^2+x-5 ?

The solutions to the equation 0=24x^3+2x^2+x-5 are x\approx 0.54401…

Find the zeros of 0=24x^3+2x^2+x-5

The zeros of 0=24x^3+2x^2+x-5 are x\approx 0.54401…

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0 = 24 x^{3} + 2 x^{2} + x - 5

x \approx 0.54401 \dots

Solution steps

0 = 24 x^{3} + 2 x^{2} + x - 5

Switch sides

24 x^{3} + 2 x^{2} + x - 5 = 0

Find one solution for

24 x^{3} + 2 x^{2} + x - 5 = 0

using Newton-Raphson:

x \approx 0.54401 \dots

Apply long division:

\frac{24 x ^{3} + 2 x ^{2} + x - 5}{x - 0.54401 \dots} = 24 x^{2} + 15.05637 \dots x + 9.19090 \dots

24 x^{2} + 15.05637 \dots x + 9.19090 \dots \approx 0

Find one solution for

24 x^{2} + 15.05637 \dots x + 9.19090 \dots = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

x \approx 0.54401 \dots

25 x^{4} - 65 x^{2} + 36 = 0

24 = r^{4}

x, x^{5} = y^{4}

x, x^{4} - 1 + y = 0

x^{12} = 3

What are the solutions to the equation 0=24x^3+2x^2+x-5 ?
The solutions to the equation 0=24x^3+2x^2+x-5 are x\approx 0.54401…
Find the zeros of 0=24x^3+2x^2+x-5
The zeros of 0=24x^3+2x^2+x-5 are x\approx 0.54401…