What are the solutions to the equation 16x^4-145x^2+324=0 ?

The solutions to the equation 16x^4-145x^2+324=0 are x= 9/4 ,x=-9/4 ,x=2,x=-2

Find the zeros of 16x^4-145x^2+324=0

The zeros of 16x^4-145x^2+324=0 are x= 9/4 ,x=-9/4 ,x=2,x=-2

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16 x^{4} - 145 x^{2} + 324 = 0

x = \frac{9}{4}, x = - \frac{9}{4}, x = 2, x = - 2

Decimal Notation

x = 2.25, x = - 2.25, x = 2, x = - 2

Solution steps

16 x^{4} - 145 x^{2} + 324 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

16 u^{2} - 145 u + 324 = 0

Solve

16 u^{2} - 145 u + 324 = 0 : u = \frac{81}{16}, u = 4

u = \frac{81}{16}, u = 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{81}{16} : x = \frac{9}{4}, x = - \frac{9}{4}

Solve

x^{2} = 4 : x = 2, x = - 2

The solutions are

x = \frac{9}{4}, x = - \frac{9}{4}, x = 2, x = - 2

x, x^{3} - 5 x + 1 = - 0.8

x^{7} = 168

x^{2} + 2 x - 9 = 2 x^{2} x

j (x) = x^{4}

x, 6 x^{2} (m + 2) x + 3 = 0

What are the solutions to the equation 16x^4-145x^2+324=0 ?
The solutions to the equation 16x^4-145x^2+324=0 are x= 9/4 ,x=-9/4 ,x=2,x=-2
Find the zeros of 16x^4-145x^2+324=0
The zeros of 16x^4-145x^2+324=0 are x= 9/4 ,x=-9/4 ,x=2,x=-2