What are the solutions to the equation 2m^3-250=0 ?

The solutions to the equation 2m^3-250=0 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

Find the zeros of 2m^3-250=0

The zeros of 2m^3-250=0 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

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2 m^{3} - 250 = 0

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

2 m^{3} - 250 = 0

Move

250

to the right side

2 m^{3} = 250

Divide both sides by

2

m^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

7 x^{4} + 2 = 8 x^{4} + 10

4 x^{3} + 16 x^{2} + 19 x + 5 = 0

- x^{3} - 3 x^{2} + 32 x - 60 = 0

4 x^{3} + 4 x^{2} - 21 x + 9 = 0

- 42 = 8 - 2 x^{3}

What are the solutions to the equation 2m^3-250=0 ?
The solutions to the equation 2m^3-250=0 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i
Find the zeros of 2m^3-250=0
The zeros of 2m^3-250=0 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i