What are the solutions to the equation 6+x^3=222 ?

The solutions to the equation 6+x^3=222 are x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

Find the zeros of 6+x^3=222

The zeros of 6+x^3=222 are x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i

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6 + x^{3} = 222

x = 6, x = - 3 + 33 i, x = - 3 - 33 i

Solution steps

6 + x^{3} = 222

Move

6

to the right side

x^{3} = 216

For

x^{3} = f (a)

the solutions are

Simplify

x = 6, x = - 3 + 33 i, x = - 3 - 33 i

(x - 4)^{2} = (x - 4)^{4}

2 x^{3} + 5 x - 1 = 0

x^{3} - x - 20 = 0

8.62 x^{3} - 4.5833 x - 0.8035 = 0

15 x^{3} + 14 x^{2} - 8 x = 9

What are the solutions to the equation 6+x^3=222 ?
The solutions to the equation 6+x^3=222 are x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i
Find the zeros of 6+x^3=222
The zeros of 6+x^3=222 are x=6,x=-3+3sqrt(3)i,x=-3-3sqrt(3)i