What are the solutions to the equation x^3-2x^2-2x+4=0 ?

The solutions to the equation x^3-2x^2-2x+4=0 are x=2,x=-sqrt(2),x=sqrt(2)

Find the zeros of x^3-2x^2-2x+4=0

The zeros of x^3-2x^2-2x+4=0 are x=2,x=-sqrt(2),x=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 2 x^{2} - 2 x + 4 = 0

x = 2, x = - 2, x = 2

Decimal Notation

x = 2, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

x^{3} - 2 x^{2} - 2 x + 4 = 0

Factor

x^{3} - 2 x^{2} - 2 x + 4 : (x - 2) (x + 2) (x - 2)

(x - 2) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 2, x = - 2, x = 2

x (x + 1) (x^{2} - 36) = 0

x^{3} - 3 x^{2} - 50 = 0

72 x^{4} - x^{2} - 1 = 0

(1 + x)^{5} = 1.24

6 x^{9} - 72 x^{7} - 7 x^{2} + 96 x - 63 = 0

What are the solutions to the equation x^3-2x^2-2x+4=0 ?
The solutions to the equation x^3-2x^2-2x+4=0 are x=2,x=-sqrt(2),x=sqrt(2)
Find the zeros of x^3-2x^2-2x+4=0
The zeros of x^3-2x^2-2x+4=0 are x=2,x=-sqrt(2),x=sqrt(2)