What are the solutions to the equation 12x^3+12x^2-24x-24=0 ?

The solutions to the equation 12x^3+12x^2-24x-24=0 are x=-1,x=-sqrt(2),x=sqrt(2)

Find the zeros of 12x^3+12x^2-24x-24=0

The zeros of 12x^3+12x^2-24x-24=0 are x=-1,x=-sqrt(2),x=sqrt(2)

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12 x^{3} + 12 x^{2} - 24 x - 24 = 0

x = - 1, x = - 2, x = 2

Solution steps

12 x^{3} + 12 x^{2} - 24 x - 24 = 0

Factor

12 x^{3} + 12 x^{2} - 24 x - 24 : 12 (x + 1) (x + 2) (x - 2)

12 (x + 1) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = - 2, x = 2

3 x^{3} = 27

3 x^{3} = 24

3 x^{3} = 81

x^{4} + 6 x^{3} + 3 x^{2} - 10 x = 0

x^{3} = - 0.027

What are the solutions to the equation 12x^3+12x^2-24x-24=0 ?
The solutions to the equation 12x^3+12x^2-24x-24=0 are x=-1,x=-sqrt(2),x=sqrt(2)
Find the zeros of 12x^3+12x^2-24x-24=0
The zeros of 12x^3+12x^2-24x-24=0 are x=-1,x=-sqrt(2),x=sqrt(2)