What are the solutions to the equation (u^2-6u+8)(2u+14)=0 ?

The solutions to the equation (u^2-6u+8)(2u+14)=0 are u=2,u=4,u=-7

Find the zeros of (u^2-6u+8)(2u+14)=0

The zeros of (u^2-6u+8)(2u+14)=0 are u=2,u=4,u=-7

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(u^{2} - 6 u + 8) (2 u + 14) = 0

u = 2, u = 4, u = - 7

Solution steps

(u^{2} - 6 u + 8) (2 u + 14) = 0

Factor

(u^{2} - 6 u + 8) (2 u + 14) : 2 (u - 2) (u - 4) (u + 7)

2 (u - 2) (u - 4) (u + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u - 2 = 0 or u - 4 = 0 or u + 7 = 0

Solve

u - 2 = 0 : u = 2

Solve

u - 4 = 0 : u = 4

Solve

u + 7 = 0 : u = - 7

The solutions are

u = 2, u = 4, u = - 7

X^{4} - X^{2} + 1 = 0

4 x^{3} = 16 x

1 - 9 x - 6 x - x^{3} = 0

(x - 3) (x + 4) (x + 5) (x - 4) = 180

6 - 3 (x + 1) = - 4 x^{2} (1 - x)

What are the solutions to the equation (u^2-6u+8)(2u+14)=0 ?
The solutions to the equation (u^2-6u+8)(2u+14)=0 are u=2,u=4,u=-7
Find the zeros of (u^2-6u+8)(2u+14)=0
The zeros of (u^2-6u+8)(2u+14)=0 are u=2,u=4,u=-7