What are the solutions to the equation -x^3-x^2+8x+12=0 ?

The solutions to the equation -x^3-x^2+8x+12=0 are x=-2,x=3

Find the zeros of -x^3-x^2+8x+12=0

The zeros of -x^3-x^2+8x+12=0 are x=-2,x=3

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- x^{3} - x^{2} + 8 x + 12 = 0

x = - 2, x = 3

Solution steps

- x^{3} - x^{2} + 8 x + 12 = 0

Factor

- x^{3} - x^{2} + 8 x + 12 : - (x + 2)^{2} (x - 3)

- (x + 2)^{2} (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = 3

2 a^{2} (a^{2} + 2) = 27 + 7 a^{2}

2 x - 53 = 2 + x^{15}

5 g^{2} + g^{3} = - 4 g

x^{4} + 35 x^{2} - 36 = 0

4 x^{3} = 256 x

What are the solutions to the equation -x^3-x^2+8x+12=0 ?
The solutions to the equation -x^3-x^2+8x+12=0 are x=-2,x=3
Find the zeros of -x^3-x^2+8x+12=0
The zeros of -x^3-x^2+8x+12=0 are x=-2,x=3