What are the solutions to the equation solvefor x,(2x+1)^4-80=1 ?

The solutions to the equation solvefor x,(2x+1)^4-80=1 are x=1,x=-2

Find the zeros of solvefor x,(2x+1)^4-80=1

The zeros of solvefor x,(2x+1)^4-80=1 are x=1,x=-2

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solve for

x, (2 x + 1)^{4} - 80 = 1

x = 1, x = - 2

Solution steps

(2 x + 1)^{4} - 80 = 1

Move

80

to the right side

(2 x + 1)^{4} = 81

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 1, x = - 2

x^{4} - 2 x^{3} + x^{2} - 2 = 0

x^{6} - 7 x^{3} + 10 = 0

4 x^{3} = 16 x^{2} - 48 x

- x^{3} + 8 x^{2} - 13 x + 2 = 0

r^{4} - r + 1 = 0

What are the solutions to the equation solvefor x,(2x+1)^4-80=1 ?
The solutions to the equation solvefor x,(2x+1)^4-80=1 are x=1,x=-2
Find the zeros of solvefor x,(2x+1)^4-80=1
The zeros of solvefor x,(2x+1)^4-80=1 are x=1,x=-2